Home » The representative for world No. 2 Alexander Zverev announces a “realistic” comeback date.
The representative for world No. 2 Alexander Zverev announces a “realistic” comeback date.
The representative for Alexander Zverev stated that the German still hopes to be able to compete at the US Open but added that a mid-September return appears more likely. During his semifinal match against Rafael Nadal at the French Open, Zverev, 25, tore several ankle ligaments.
Zverev has been sidelined since, but he is recovering well from an ankle operation. On August 29, the US Open will begin, and after skipping Wimbledon, Zverev would undoubtedly like to avoid consecutive Grand Slam losses. According to a spokesman who was reported by Tennis365 as saying to Reuters, “Sascha is recovering well and is still expecting that he can be ready for the US Open.”
To be able to predict whether he will be able to compete there or not, though, is still too early.
September is more likely to see Zverev return.
Zverev hopes to lead Germany in Group C against France, Belgium, and Australia. Hamburg will be one of four host cities for the Davis Cup Finals group stage.
The Davis Cup Finals group stage runs from September 13 until September 18. The spokesperson continued, “Davis Cup in Hamburg in September appears more feasible, but we have our fingers crossed that he will be ready early.”
So, before Tokyo, he ought to be able to play in a few events. Since he began working out in the gym, Zverev no longer needs crutches. The days are lengthy, Zverev remarked. “You get going early and wrap things off in the evening.
We perform a lot of workouts, and new ones are always being added. Treatment is given to the foot, and its strength and stability are rebuilt together with its mobility. In some instances, regular running and walking must be relearned. I workout on the treadmill, the bicycle, and in the water for sprints.
Whether Zverev will be able to recuperate in time for the US Open, where he won his first Grand Slam match in 2020, is yet unknown.